0=1.6-3.2x+0.6x^2

Solution for 0=1.6-3.2x+0.6x^2 equation:

0=1.6-3.2x+0.6x^2

We move all terms to the left:

0-(1.6-3.2x+0.6x^2)=0

We add all the numbers together, and all the variables

-(1.6-3.2x+0.6x^2)=0

We get rid of parentheses

-0.6x^2+3.2x-1.6=0

a = -0.6; b = 3.2; c = -1.6;
Δ = b2-4ac
Δ = 3.22-4·(-0.6)·(-1.6)
Δ = 6.4
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(3.2)-\sqrt{6.4}}{2*-0.6}=\frac{-3.2-\sqrt{6.4}}{-1.2}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(3.2)+\sqrt{6.4}}{2*-0.6}=\frac{-3.2+\sqrt{6.4}}{-1.2}
$